(4k^2-12k+9)/(4k)=0

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Solution for (4k^2-12k+9)/(4k)=0 equation: 



(4k^2-12k+9)/(4k)=0



Domain of the equation: 4k!=0

k!=0/4

k!=0

k∈R



We multiply all the terms by the denominator


(4k^2-12k+9)=0

We get rid of parentheses

4k^2-12k+9=0

a = 4; b = -12; c = +9;
Δ = b2-4ac
Δ = -122-4·4·9
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$k=\frac{-b}{2a}=\frac{12}{8}=1+1/2$

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